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Last-Minute Formula Sheet
Inverse Trigonometric Functions (ITF)
Principal-value domains and ranges
Core identities
\[
\sin^{-1}x+\cos^{-1}x=\frac{\pi}{2}
\]
\[
\tan^{-1}x+\cot^{-1}x=\frac{\pi}{2}
\]
\[
\sec^{-1}x+\cosec^{-1}x=\frac{\pi}{2}
\]
\[
\sin^{-1}(-x)=-\sin^{-1}x,\quad \tan^{-1}(-x)=-\tan^{-1}x
\]
\[
\cos^{-1}(-x)=\pi-\cos^{-1}x,\quad \cot^{-1}(-x)=\pi-\cot^{-1}x
\]
Addition and subtraction
\[
\tan^{-1}x+\tan^{-1}y=\tan^{-1}\left(\frac{x+y}{1-xy}\right),\quad xy<1
\]
\[
\tan^{-1}x-\tan^{-1}y=\tan^{-1}\left(\frac{x-y}{1+xy}\right),\quad xy>-1
\]
For \(xy>1\), adjust the result by \(\pm\pi\) according to the principal range.
\[
2\tan^{-1}x=\tan^{-1}\left(\frac{2x}{1-x^2}\right)
\]
Useful conversions:
\[
\sin^{-1}x=\tan^{-1}\left(\frac{x}{\sqrt{1-x^2}}\right),\quad |x|<1
\]
\[
\cos^{-1}x=\tan^{-1}\left(\frac{\sqrt{1-x^2}}{x}\right)\quad (x>0)
\]
\[
\tan^{-1}x=\sin^{-1}\left(\frac{x}{\sqrt{1+x^2}}\right)
\]
Differentiation — Important Formulas
Basic derivatives
\[
\frac{d}{dx}(c)=0,\quad \frac{d}{dx}(x^n)=nx^{n-1}
\]
\[
\frac{d}{dx}(e^x)=e^x,\quad \frac{d}{dx}(a^x)=a^x\log a
\]
\[
\frac{d}{dx}(\log x)=\frac{1}{x},\quad \frac{d}{dx}(\log_a x)=\frac{1}{x\log a}
\]
Trigonometric functions
\[
(\sin x)'=\cos x,\quad (\cos x)'=-\sin x
\]
\[
(\tan x)'=\sec^2x,\quad (\cot x)'=-\cosec^2x
\]
\[
(\sec x)'=\sec x\tan x,\quad (\cosec x)'=-\cosec x\cot x
\]
Inverse trigonometric functions
\[
(\sin^{-1}x)'=\frac{1}{\sqrt{1-x^2}}
\]
\[
(\cos^{-1}x)'=-\frac{1}{\sqrt{1-x^2}}
\]
\[
(\tan^{-1}x)'=\frac{1}{1+x^2}
\]
\[
(\cot^{-1}x)'=-\frac{1}{1+x^2}
\]
\[
(\sec^{-1}x)'=\frac{1}{|x|\sqrt{x^2-1}}
\]
\[
(\cosec^{-1}x)'=-\frac{1}{|x|\sqrt{x^2-1}}
\]
Rules
\[
(u\pm v)'=u'\pm v'
\]
\[
(uv)'=u'v+uv'
\]
\[
\left(\frac{u}{v}\right)'=\frac{vu'-uv'}{v^2}
\]
\[
\frac{d}{dx}f(g(x))=f'(g(x))g'(x)
\]
Chain-rule forms
\[
(\sin u)'=\cos u\cdot u',\quad (\cos u)'=-\sin u\cdot u'
\]
\[
(\tan u)'=\sec^2u\cdot u',\quad (e^u)'=e^u\cdot u'
\]
\[
(\log u)'=\frac{u'}{u}
\]
\[
(\sin^{-1}u)'=\frac{u'}{\sqrt{1-u^2}},\quad (\tan^{-1}u)'=\frac{u'}{1+u^2}
\]
Parametric and implicit differentiation
If \(x=f(t)\), \(y=g(t)\), then
\[
\frac{dy}{dx}=\frac{dy/dt}{dx/dt}
\]
If \(F(x,y)=0\), differentiate both sides with respect to \(x\), treating \(y\) as a function of \(x\).
Logarithmic differentiation
If \(y=u^v\), then
\[
\log y=v\log u
\]
\[
\frac{y'}{y}=v'\log u+v\frac{u'}{u}
\]
Continuity and Differentiability
Continuity at \(x=a\)
\[
\lim_{x\to a}f(x)=f(a)
\]
Equivalent condition:
\[
\text{LHL}=\text{RHL}=f(a)
\]
For a piecewise function, calculate the left-hand limit, right-hand limit, and actual value separately.
Differentiability at \(x=a\)
\[
\text{LHD}=\text{RHD}
\]
where
\[
\text{LHD}=\lim_{h\to0^-}\frac{f(a+h)-f(a)}{h},
\quad
\text{RHD}=\lim_{h\to0^+}\frac{f(a+h)-f(a)}{h}
\]
Key facts
Differentiability implies continuity.
Continuity does not necessarily imply differentiability.
A function may fail to be differentiable at a corner, cusp, sharp point, or discontinuity.
Polynomials, exponential functions, logarithmic functions on their domains, and standard trigonometric functions are continuous and differentiable wherever defined.
\(|x|\) is continuous at \(x=0\), but not differentiable there.
Common limits
\[
\lim_{x\to0}\frac{\sin x}{x}=1
\]
\[
\lim_{x\to0}\frac{\tan x}{x}=1
\]
\[
\lim_{x\to0}\frac{1-\cos x}{x^2}=\frac12
\]
\[
\lim_{x\to0}\frac{e^x-1}{x}=1
\]
\[
\lim_{x\to0}\frac{\log(1+x)}{x}=1
\]
Applications of Derivatives — Increasing and Decreasing
For a function \(f(x)\):
If \(f'(x)>0\) on an interval, \(f\) is increasing there.
If \(f'(x)<0\) on an interval, \(f\) is decreasing there.
If \(f'(x)=0\), the point is a critical/stationary point; test the sign of \(f'\) on both sides.
Sign-chart method
Find \(f'(x)\).
Solve \(f'(x)=0\) and identify points where \(f'(x)\) is undefined.
Mark these points on the number line.
Test the sign of \(f'(x)\) in each interval.
Write intervals of increase and decrease.
First-derivative test
\[
f':+\to- \Rightarrow \text{local maximum}
\]
\[
f':-\to+ \Rightarrow \text{local minimum}
\]
For \(f'(x)=0\) throughout an interval, the function is constant on that interval.
Mensuration — Cube and Cuboid
Cuboid
Let length \(l\), breadth \(b\), height \(h\).
\[
\text{Volume}=lbh
\]
\[
\text{LSA}=2h(l+b)
\]
\[
\text{TSA}=2(lb+bh+hl)
\]
\[
\text{Diagonal}=\sqrt{l^2+b^2+h^2}
\]
Cube
Let side \(a\).
\[
\text{Volume}=a^3
\]
\[
\text{LSA}=4a^2
\]
\[
\text{TSA}=6a^2
\]
\[
\text{Face diagonal}=a\sqrt2
\]
\[
\text{Space diagonal}=a\sqrt3
\]
Mensuration — Cylinder
Let radius \(r\), height \(h\).
\[
\text{Base area}=\pi r^2
\]
\[
\text{CSA}=2\pi rh
\]
\[
\text{TSA}=2\pi r(h+r)
\]
\[
\text{Volume}=\pi r^2h
\]
For a hollow cylinder with outer radius \(R\), inner radius \(r\), height \(h\):
\[
\text{Volume of material}=\pi h(R^2-r^2)
\]
Mensuration — Cone
Let radius \(r\), height \(h\), slant height \(l\).
\[
l=\sqrt{r^2+h^2}
\]
\[
\text{CSA}=\pi rl
\]
\[
\text{TSA}=\pi r(l+r)
\]
\[
\text{Volume}=\frac13\pi r^2h
\]
Frustum of a cone
Let larger radius \(R\), smaller radius \(r\), height \(h\), slant height \(l\).
\[
l=\sqrt{h^2+(R-r)^2}
\]
\[
\text{CSA}=\pi(R+r)l
\]
\[
\text{TSA}=\pi(R+r)l+\pi R^2+\pi r^2
\]
\[
\text{Volume}=\frac13\pi h(R^2+r^2+Rr)
\]
Mensuration — Sphere and Hemisphere
Sphere
Let radius \(r\).
\[
\text{Surface area}=4\pi r^2
\]
\[
\text{Volume}=\frac43\pi r^3
\]
Hemisphere
\[
\text{CSA}=2\pi r^2
\]
\[
\text{TSA}=3\pi r^2
\]
\[
\text{Volume}=\frac23\pi r^3
\]
Quick reminders
Use the same units throughout.
Area is in square units; volume is in cubic units.
\(\text{CSA/LSA}\) excludes the base(s); \(\text{TSA}\) includes all exposed surfaces.
In calculus questions, use radians for trigonometric differentiation and limits.
For ITF answers, always check the principal range before finalising the value.